12x^2-12x-20=0

Solution for 12x^2-12x-20=0 equation:

12x^2-12x-20=0

a = 12; b = -12; c = -20;
Δ = b2-4ac
Δ = -122-4·12·(-20)
Δ = 1104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1104}=\sqrt{16*69}=\sqrt{16}*\sqrt{69}=4\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{69}}{2*12}=\frac{12-4\sqrt{69}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{69}}{2*12}=\frac{12+4\sqrt{69}}{24}
$